National parks near San Lucas Quiaviní, Oaxaca
The closest national park to San Lucas Quiaviní, Oaxaca is Benito Juárez National Park — about 41.8 km (26 mi) away, or roughly 57 min of driving.
3 parks are close enough to do as a day trip: Benito Juárez, Huatulco, and Lagunas de Chacahua.
Benito Juárez
Huatulco
Lagunas de Chacahua
Cañón del Río Blanco
Pico de Orizaba
Sistema Arrecifal Veracruzano
National parks near San Lucas Quiaviní
| Park | Straight-line distance | Estimated drive | Realistic trip |
|---|---|---|---|
| Benito Juárez National Park | 41.8 km (26 mi) | 57 min | Doable as a day trip |
| Huatulco National Park | 135 km (83.6 mi) | 2 hr 26 min | Doable as a day trip |
| Lagunas de Chacahua National Park | 166 km (103 mi) | 2 hr 53 min | Doable as a day trip |
| Cañón del Río Blanco National Park | 227 km (141 mi) | 3 hr 47 min | Best as a weekend |
| Pico de Orizaba National Park | 252 km (157 mi) | 4 hr 9 min | Best as a weekend |
| Sistema Arrecifal Veracruzano National Park | 264 km (164 mi) | 4 hr 20 min | Best as a weekend |
| General Juan N. Álvarez National Park | 288 km (179 mi) | 4 hr 41 min | Best as a weekend |
| Cofre de Perote National Park | 298 km (185 mi) | 4 hr 50 min | Best as a weekend |
| La Malinche National Park | 309 km (192 mi) | 5 hr | Best as a weekend |
| Xicoténcatl National Park | 327 km (203 mi) | 5 hr 16 min | Best as a weekend |
Towns and cities in San Lucas Quiaviní
Common questions
What is the closest national park to San Lucas Quiaviní?
Benito Juárez National Park, about 41.8 km (26 mi) away and roughly 57 min of driving.
Which national parks can I visit from San Lucas Quiaviní in a day?
Benito Juárez National Park, Huatulco National Park, and Lagunas de Chacahua National Park — all within about three hours' drive.